emf of cell Ni | Ni²⁺(1.0 M) || Au³⁺(1.0 M) | Au is..., if E... — Chemistry | Mockzy

EasyChemistryEMF of cell

+4 / -1

emf of cell Ni | Ni²⁺(1.0 M) || Au³⁺(1.0 M) | Au is..., if E°(Ni²⁺/Ni) = −0.25 V and E°(Au³⁺/Au) = +1.50 V

+1.25 V

−1.75 V

+1.75 V

+4.0 V

At equilibrium -

Normal Al–AlCl₃ coupled with standard hydrogen electrode gives an emf of 1.66 V.

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