Three Faradays of electricity are passed through molten AlCl₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the catho

Question

Three Faradays of electricity are passed through molten AlCl₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of-

Accepted Answer

Answer: 1 mole : 1.5 mole : 3 mole — 3F gives: Al³⁺ → Al = 3F per mol ⇒ 1 mol Cu²⁺ → Cu = 2F per mol ⇒ 1.5 mol Na⁺ → Na = 1F per mol ⇒ 3 mol Ratio = 1 : 1.5 : 3

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