As we know that all the d-block elements exhibit various valencies or have variable oxidation numbers.
But scandium does not show because scandium has partially filled d-orbitals in the ground state.
electronic configuration of the valence shell is (3d1 4s2).
So, removing these 3 electrons from its d and s orbital forms a very stable inert gas configuration.
It losses 1 electron from d orbital and 2 electrons from s orbital to form a Sc3+ ion. Therefore, option – (4) Sc is the correct ans.
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