Coordination Compound Questions

Which one of the following pairs of isomers and types of isomerism are correctly matched – (a) [Co(NH₃)₅(NO₂)]Cl₂ and [Co(NH₃)₅(ONO)]Cl₂....Linkage (b) [Cu(NH₃)₄][PtCl₄] and [Pt(NH₃)₄][CuCl₄].....co-ordination (c) [Pt(NH₃)₄Cl₂]Br₂ and [Pt(NH₃)₄Br₂]Cl

[(C₆H₅)₂Pd(SCN)₂] and [(C₆H₅)₂Pd(NCS)₂] are –

[Cr(H₂O)₆]³⁺ ion has d-electrons equal to –

The complex that violates the EAN rule –

The complex ion which has no 'd' electrons in the central metal atom is –

Aqua-regia reacts with Pt to yield –

Which one is the most likely structure of CrCl₃.6H₂O if 1/3 of total chlorine of the compound is precipitated by adding AgNO₃ to its aqueous solution –

The geometry of some complex ions are given against them – (1) [Ag(NH₃)₂]⁺ – Linear (2) [MnCl₄]²⁻ – Tetrahedral (3) [Cu(NH₃)₄]²⁺ – Square planar (4) [Ni(CN)₄]²⁻ – square planar The correct match is –

The number of geometrical isomers for [Pt(NH₃)₂Cl₂] is –

Which of the following complexes has the least molar conductivity in the solution –

Which of the following is an outer orbital complex –

For the t₂g⁶ e_g² system, the value of magnetic moment (μ) is –

If Δ₀ < P, the correct electronic configuration for d⁴ system will be –

In an octahedral crystal field, the t₂g orbitals are –

Hexafluorocobaltate(III) ion is found to be high spin complex, the probable hybrid state of cobalt in it is –

The complex ion [Cu(NH₃)₄]²⁺ has –

Which order is correct in spectrochemical series of ligands –

Complexes with CN⁻ ligands are usually –

Which is correct in the case of [Fe(CN)₆]⁴⁻ complex –

Which complex has square planar structure –

Which of the following contains one unpaired electron in the 4p orbitals –

The complex ions [Fe(CN)₆]³⁻ and [Fe(CN)₆]⁴⁻ –

The complex ion [Cu(NH₃)₄]²⁺ is –

Theoretically the No. of geometrical isomers expected for octahedral complex [Mabcdef] is –

The complexes given below are –

Out of the following which will not show geometrical isomerism –

Cis-trans-isomerism is found in square planar complexes of molecular formula (a and b are monodentate ligands) –

A square planar complex represented as it will show isomerism –

The phenomenon of optical activity will be shown by –

A complex shown below –

[Co(NH₃)₅Br]SO₄ and [Co(NH₃)₅SO₄]Br are isomers –

Which would exhibit co-ordination isomerism –

Which one of the following octahedral complexes will not show geometrical isomerism (A and B are monodentate ligands) –

Which of the following is not optically active –

Geometrical isomerism in coordination compounds is exhibited by –

The complex ions [Co(NH₃)₅(NO₂)]²⁺ and [Co(NH₃)₅(ONO)]²⁺ are called –

In coordination compounds, the hydrate isomers differ –

What is the oxidation number of chromium in the dimeric hydroxo bridged species

Which of the following statement is incorrect about [Fe(H₂O)₅NO]SO₄ –

The chloro-bis (ethylenediamine) nitro cobalt (III) ion is –

Give the IUPAC name of the complex compound [Co(NH₃)₄(H₂O)Br](NO₃)₂ –

In brown ring complex compound [Fe(H₂O)₅NO]SO₄, the oxidation state of Fe is –

The IUPAC name of the complex [CrCl₂(H₂O)₄]NO₃ is –

K₃[Fe(CN)₆] is – (a) Potassium hexacyanoferrous (III) (b) Potassium hexacyanoferrate (III) (c) Potassium ferricyanide (d) Hexa cyano ferrate (III) potassium Correct answer is –

The IUPAC name of Fe(CO)₅ is –

The formula of the complex tris (ethylene diamine) cobalt (III) sulphate is –

The IUPAC name for K₂[OsCl₅N] is –

The IUPAC name for [Co(NCS)(NH₃)₅]Cl₂ is–

The IUPAC name [Co(NH₃)₆] [Cr(CN)₆] is –

The IUPAC name of K₂[Cr(CN)₂O₂(O₂)(NH₃)] is–