For a reaction AB₅ → AB + 4B The rate can be expressed in following ways So the correct relation between K and K₁ is-

Answer: K₁ = 4K — 1 mole AB₅ produces 4 moles B. Therefore d[B]/dt = 4(−d[AB₅]/dt).

For a reaction AB₅ → AB + 4B The rate can be expressed in fo... — Chemistry | Mockzy

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For a reaction AB₅ → AB + 4B The rate can be expressed in following ways $- \frac{d [ A B _{5} ]}{d t} = K [A B_{5}]; \frac{d [ B ]}{d t} = K_{1} [A B_{5}]$ So the correct relation between K and K₁ is-

K₁ = K

K₁ = 2K

K₁ = 4K

2K₁ = K

The rate of reaction at 273 K is R₀. The rate of reaction at 313 K will be (Assu

For a second order reaction, the graph plotted between [A]⁻¹ and time 't' is sho

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