The chemical reaction 2O₃ → 3O₂ proceeds as follows - O₃ ⇌ O₂ + O ............(fast) O + O₃ → 2O₂ ............(slow) The rate law expression should be -

Answer: r = k [O₃]² [O₂]⁻¹ — Using equilibrium approximation, [O] ∝ [O₃]/[O₂]. Hence rate = k[O][O₃] = k[O₃]²/[O₂].

The chemical reaction 2O₃ → 3O₂ proceeds as follows - O₃ ⇌ O... — Chemistry | Mockzy

EasyChemistryRate law, Unit of Rate constant, order of reaction

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r = k [O₃]²

r = k [O₃]² [O₂]⁻¹

r = k [O₃] [O₂]

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