EasyChemistryIntegrated Rate law
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A radioactive isotope decomposes according to the first order with half life period of 15 hrs. 80% of the sample will decompose in -
A
15 × 0.8 hr.
B
15 × (log 8) hr.
C
15 × (log5 / log2) hr. (or 34.83) hr.
D
15 × 10/8 hr.
Explanation
80% decomposed ⇒ 20% remains. N/N₀ = 0.2 = 1/5 t = t₁/₂ × (log5/log2) = 15 × (log5/log2) ≈ 34.83 h
Previous
The rate constant for a second order reaction is 8.0 × 10⁻⁴ litre mol⁻¹ min⁻¹. H
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