For a chemical reaction, 2A + 2B ⟶ C + D, the order of reaction is one with respect to A and one with respect to B. The initial rate of the reaction is 4 × 10⁻² mol L⁻¹ s⁻¹. When 50% of the reactants

Question

For a chemical reaction, 2A + 2B ⟶ C + D, the order of reaction is one with respect to A and one with respect to B. The initial rate of the reaction is 4 × 10⁻² mol L⁻¹ s⁻¹. When 50% of the reactants are converted into products, the rate of reaction would become-

Accepted Answer

Answer: 1 × 10⁻² mol L⁻¹ s⁻¹ — Rate = k[A][B] At 50% conversion: [A] and [B] become half. New rate = k(A/2)(B/2) = (1/4) original rate = (1/4)(4 × 10⁻²) = 1 × 10⁻² mol L⁻¹ s⁻¹

Practice Chemistry Exams