Using the data given below the order and rate constant for the reaction : CH₃CHO(g) → CH₄(g) + CO(g)

Answer: 2,[k = 2.0 ℓ/mol sec] — Doubling concentration from 0.10 to 0.20 increases rate four times. Hence order = 2. k = Rate/[A]² = 0.020/(0.10)² = 2.0 ℓ mol⁻¹ sec⁻¹

Using the data given below the order and rate constant for t... — Chemistry | Mockzy

EasyChemistryRate law, Unit of Rate constant, order of reaction

+4 / -1

2,[k = 2.0 ℓ/mol sec]

0,[k = 2.0 mol/ℓ sec]

2,[k = 1.5 ℓ/mol sec]

1,[k = 1.5 sec⁻¹]

The following data pertain to reaction between A and B : Which of the following

For which of the following, the units of rate constant and rate of the reaction

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