Consider two radiations of wavelengths
λ₁ = 2000 Å
λ₂ = 6000 Å
The ratio of the energies of these two radiations (E₁/E₂) is _____ (Nearest integer).
We know that the energy of a photon is given by the formula
E = hc/λ where h = Planck’s constant c = velocity of light λ = wavelength of the radiation.
For the two radiations, E₁/E₂ = (hc/λ₁) / (hc/λ₂) = λ₂/λ₁
λ₁ = 2000 Å, λ₂ = 6000 Å
E₁/E₂ = 6000/2000 = 3
Final Answer E₁/E₂ = 3 Hence, the ratio of energies of the two radiations is 3 (nearest integer).
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