Liquid Solutions
206 questions · Click an option and press Check Answer to reveal the result
The phase diagrams for a pure solvent (solid line) and a corresponding solution (containing a nonvolatile solute and represented by the dashed lines) are shown below. 
Choose the correct option.
A = ΔTb m and B = ΔTf m
A = ΔTf m and B = ΔTb m
A = ΔTf and B = ΔTb
A = ΔTb and B = ΔTf
Assertion : Reverse osmosis is used to purify sea water.
Reason : Solvent molecules pass from concentrate solution to pure solvent through semipermeable membrane if high pressure (> π) is applied on solution side
If pKa = −log Ka = 4, and Ka = Cα² then van't Hoff factor for weak monobasic acid when C = 0.01 M is -
Calculate the amount of CO₂ in moles that will dissolve in enough water to form 900 mL of solution at 20°C if partial pressure of CO₂ is 1 atm and kH for CO₂ is 2.3 × 10⁻² mol L⁻¹ atm⁻¹.
A solution containing 12.5g of non-electrolyte substance in 175g of water gave boiling point elevation of 0.70K. Calculate the molar mass of the substance. Molal elevation constant (Kb) for water 0.52K kg mol−1
Given at 350 K , p°A = 300 torr and p°B = 800 torr, the composition of the mixture having a boiling point of 350 K is -
XA = 0.08
XA = 0.06
XA = 0.04
XA = 0.02
K2[PtCl4]
K2[PtCl6]
K3[PtCl5]
K[PtCl3]
Ratio of (ΔTb/Kb) of 10 g of AB₂ and 14 g of A₂B in 100 g solvent in their respective solutions (AB₂ & A₂B both are non-electrolytes) is 1 mol kg⁻¹ in both cases. Hence atomic wt. of A and B respectively-
The normality of 0.3 M phosphorous acid (H3PO3) is -
0.1
0.9
0.3
0.6
b.p. : Y < Z < X
At a given temperature, total vapour pressure in Torr of a mixture of volatile components A and B is given by
P = 120 − 75 XB
Hence, vapour pressure of pure A and B respectively (in Torr) are -
For a solution containing non-volatile solute, the relative lowering of vapour pressure is 0.2. If the solution contains 5 moles in all, which of the following are true?
I. Mole fraction of solute = 0.2
II. Number of moles of solute = 0.2
III. Number of moles of solvent = 4
IV. Mole fraction of solvent = 0.2
0.2 molal acid HX is 20% ionised in solution Kf = 1.86 K molality–1. The freezing point of the solution is
-0.45
-0.90
-0.30
-0.53
Decimolar solution of potassium ferricyanide, K3[Fe(CN)6], has osmotic pressure 3.94 atm at 27°C. Hence percent ionisation of the solute is -
Consider following solutions -
I : 1 M aq. glucose
II : 1 M aq. sodium chloride
III : 1 M benzoic acid in benzene
IV : 1 M ammonium phosphate
Select incorrect statement -
Aqueous solutions of 0.004 M Na2SO4 and 0.01 M Glucose are isotonic. The degree of dissociation of Na2SO4 is
25%
60%
75%
85%
For an ideal binary liquid solution with P°A > P°B which relation between XA (mole fraction of A in liquid phase) & YA (mole fraction of A in vapour phase) is correct. XB & YB are mole fractions of B in liquid & vapour phase respectively-
XA = YA
XA > YA
XA/XB < YA/YB
XA, YA, XB, YB cannot be correlated
ΔTf
ΔTb
Kb
Match List-I with List-II

The correct option is
The V.P. curve of same solute in the same solvent are shown. The curves are parallel to each other and do not intersect. The concentration of solutions are in order of-

Y gm of non-volatile solute of molar mass M is dissolved in 250 g of benzene. If Kb is molal elevation constant, the value of ΔT is given by-
.
.
.
.
ΔSmix = 0
ΔVmix = 0
ΔHmix = 0
Consider following vapour pressure composition graph. Hence-
