Haloalkanes & Haloarenes

The major product of the following reaction is :

The correct stability order of the following diazonium salts is

The best reagent for converting ethanol to chloroethane is -

Of the following, which is an S_N1 reaction -

Consider the following reaction sequence.

$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\equiv \mathrm{CH}\underset{2\mathrm{mole}}{\overset{\mathrm{HCl}}{\to }}A\underset{\mathrm{heat}}{\overset{aq.KOH}{\to }}B$

The products (A) and (B) are, respectively -

Consider the following reaction sequence.

$\mathrm{C}{\mathrm{H}}_3\mathrm{C}\equiv \mathrm{CH}\underset{\mathrm{HgS}{\mathrm{O}}_4}{\overset{aq.{\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4}{\to }}A\underset{\mathrm{heat}}{\overset{\mathrm{PC}{\mathrm{l}}_5}{\to }}B$

The product (A) and (B) are, respectively -

Compound (A), C₈H₉Br, gives a white precipitate when warmed with alcoholic AgNO₃. Oxidation of (A) gives an acid (B), C₈H₆O₄. (B) easily forms anhydride on heating. Identify the compound (A).

The reaction sequence $\mathrm{C}{\mathrm{H}}_3\mathrm{CC}{\mathrm{l}}_3\underset{\mathrm{hydrolysis}}{\overset{\mathrm{Alkaline}}{\to }}A\underset{\mathrm{AgN}{\mathrm{O}}_3}{\overset{\mathrm{N}{\mathrm{H}}_4\mathrm{OH}}{\to }}B\underset{\mathrm{CC}{\mathrm{l}}_4}{\overset{\mathrm{B}{\mathrm{r}}_2}{\to }}C$

A and C in the above sequence are respectively -

In the reaction RCOOAg + Br₂ $\stackrel{\mathrm{CC}{\mathrm{l}}_4}{\to }$ RBr + CO₂ + AgBr The intermediate formed is -

In the following reaction

tert-Butyl bromide + HC≡CNa →

the substrate is transformed into -

The S_N2 reactivity order for halides :-

Unimolecular nucleophilic substitution [S_N1] involves ............... steps, while bimolecular nucleophilic substitution involves ............... steps

In reaction C₂H₅OH + HX $\stackrel{\mathrm{Zn}{\mathrm{X}}_2}{\to }$ C₂H₅X + H₂O the order of reactivity of HX is -

CH₃Br $\stackrel{\mathrm{KCN}}{\to }A\stackrel{+4H}{\to }$ CH₃CH₂NH₂

IUPAC name of A is -

In the reaction CH₃CHCl₂ $\stackrel{aq.KOH}{\to }$ X. X is -

Consider the following reaction.

The product formed is -

In S_N1 reaction, the first step involves the formation of -

(R)-2-Bromooctane $\stackrel{(\mathrm{i})\mathrm{Mg}(\mathrm{ii})\mathrm{C}{\mathrm{O}}_2(\mathrm{iii}){\mathrm{H}}^{+}}{\to }$ X Product X is

In the following reaction sequence.

The product (B) will be

Consider the following reaction sequence.

The major end product formed is -

Major product for the reaction is

The yield of alkyl bromide obtained as a result of heating the dry silver salt of carboxyic acid with bromine what will be the order of formation w.r.t. alkyl bromide

$\mathrm{C}{\mathrm{H}}_3\mathrm{COC}{\mathrm{H}}_3\underset{\mathrm{N}{\mathrm{a}}_2\mathrm{C}{\mathrm{O}}_3}{\overset{{\mathrm{I}}_2}{\to }}(A)\stackrel{\mathrm{Ag}\mathrm{powder}}{\to }(B)\underset{\mathrm{H}{\mathrm{g}}^{++}}{\overset{{\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4}{\to }}(C).$

Product A, B & C are -

For CH₃Br + OH^- ⟶ CH₃OH + Br^- the rate of reaction is given by the expression -

Given below are two statements :

Statement I : CH₃ – O – CH₂ – Cl will undergo SN₁ reaction though it is a primary halide.

Statement II : CH₃ – C – CH₂ – Cl will not undergo SN₂ reaction very easily though it is a primary halide. In the light of the above statements, choose the most appropriate answer from the options given below:

Neopentyl bromide is allowed to react with sodium ethoxide in ethanol. The major product formed in the reaction is -

Which one of the following reaction is known as strecker's reaction -

Ether is -

A $\stackrel{{\mathrm{O}}^{-}\mathrm{Br}}{\to }$ CHBr₃

Here A is -

$(A)\stackrel{\mathrm{C}{\mathrm{l}}_2}{\to }(B)\stackrel{aq.KOH}{\to }(C)\stackrel{[\mathrm{O}]}{\to }\mathrm{C}{\mathrm{H}}_3\mathrm{CHO}$

Identify A, B & C -

Which of the following reactions is expected to take place by S_N2 mechanism ?

Find out number of possible E₁ products from following reaction. (Excluding stereoisomers)

CH₃CH₂I $\stackrel{\mathrm{KCN}}{\to }$ $\stackrel{{\mathrm{H}}_2\mathrm{O},\mathrm{\Delta }}{\to }$ ? Here the end product would be -

In the preparation of ethyl chloride by the reaction $\mathrm{C}{\mathrm{H}}_3\mathrm{C}{\mathrm{H}}_2\mathrm{OH}+\mathrm{HCl}\underset{\mathrm{ZnC}{\mathrm{l}}_2}{\overset{\mathrm{anhydrous}}{\to }}\mathrm{C}{\mathrm{H}}_3\mathrm{C}{\mathrm{H}}_2\mathrm{Cl}+{\mathrm{H}}_2\mathrm{O}$ the major reason for using anhydrous ZnCl₂ as a catalyst is that -

R–X $\stackrel{\mathrm{Z}}{\to }$ R–NO₂ The reagent Z in the above reaction is -

(CH₃)₃CBr + OH^- ⟶ (CH₃)₃COH + Br^-

Which of the following statements is true for the above reaction -

The order of reactivity of the following alkyl halides for a SN₂ reaction is

Consider the following sequence of reactions.

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}\underset{\mathrm{DMSO},\mathrm{heat}}{\overset{\mathrm{KCN}}{\to }}X\underset{\mathrm{Prolonged}\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }}Y$

The products (X) and (Y) are, respectively -

The order of decreasing S_N1 reactivities of the halides

I : CH₃CH₂CH₂Cl II : CH₂=CHCHClCH₃ III : CH₃CH₂CHClCH₃

is -

when Benzenediazium chloride react with HBF₄ it form compound X. X on heating gives Y and Z alongwith BF₃. X on reaction with NaNO₂, Cu/heat it again form A and Z but with NaBF₄

Products A and Y respectively are

In the reaction

the major product formed is -

$\mathrm{C}{\mathrm{H}}_3\mathrm{CC}{\mathrm{l}}_3\underset{\mathrm{hydrolysis}}{\overset{\mathrm{alkaline}}{\to }}A\stackrel{\mathrm{AgOH}}{\to }B\underset{\mathrm{CC}{\mathrm{l}}_4}{\overset{\mathrm{B}{\mathrm{r}}_2}{\to }}C$

A and C in the above sequence are respectively

Consider the following sequence of reactions.

$(A)({\mathrm{C}}_3{\mathrm{H}}_6\mathrm{C}{\mathrm{l}}_2)\underset{\mathrm{heat}}{\overset{alc.KOH}{\to }}B\underset{2.{\mathrm{H}}_2{\mathrm{O}}_2/O{\mathrm{H}}^{-}}{\overset{1.{\mathrm{B}}_2{\mathrm{H}}_6}{\to }}C$

$A\underset{\mathrm{heat}}{\overset{aq.KOH}{\to }}C$

The compound (A) is -

Consider the following statements.

a. The correct decreasing order of reactivity of alkyl halides for a SN₂ reaction is RI > RBr > RCl > RF (R = alkyl)

b. Allylic and benzylic halides show high reactivity towards SN₁ reaction.

c. SN₁ reaction is generally carried out in polar protic solvent like water.

d. Boiling point of 2-Bromobutane is higher than that of 2-Bromo-2-methylpropane.

The correct statement(s) is/are