Aldehyde , Ketones & Carboxylic Acid
10 questions · Click an option and press Check Answer to reveal the result
(CH3)2C = CHCOCH3 can be oxidised to (CH3)2C=CH.COOH by -
Chromic acid
NaOI
Cu at 575 K
KMnO4
CH3 – CH2 – CHO Product. The product in the above reaction is:
CH3 – CH2COOH
CH3– CH2–CH2OH


Which of the reagent is used to convert 2-Butanone into propanoic acid
NaOH , I2 / H+
Tollen’s reagent
Fehling solution
NaOH , NaI / H+
Which of the following carboxylic acids undergo decarboxylation easily
C6H5CO — CH2COOH
C6H5COCOOH


Among the given compounds, the most susceptible to nucleophilic attack at the carbonyl group is
MeCOCl
MeCHO
MeCOOMe
MeCOOCOMe
Which gives a ketone on treating with a Grignard’s reagent -
Formaldehyde
Ethyl alcohol
Methyl cyanide
Methyl iodide
The product obtained in the following reaction is:
CH₃–CH₂–COOH + Br₂ / red P →
In the reaction sequence : A B Acetone C
A, B and C are
CH3CHO, aldol, phorone
HCOOH, (HCOO)2Ca, mesityl oxide
CH3COOH, (CH3COO)2Ca, mesitylene
CH3COOH, (CH3COO)2Ca, pinacol
Consider the given statements
(a) Ethyl benzoate on acidic hydrolysis gives benzoic acid and ethanol.
(b) 1-Decanol on reaction with Jones reagent gives decanoic acid as major product.
(c) Phenylmagnesium bromide on reaction with dry ice followed by acidic hydrolysis gives benzoic acid as major product.
(d) Benzamide when heated with P₂O₅ gives aniline as major product.
The correct statements are
Ethyl ester P. The product P will be :



